/*
Problem 1
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
Answer:	233168
*/

#include <iostream>

using namespace std;

int main(){

int res = 0;

for(int i = 1; i< 1000;i++){
if(i % 3 == 0 or i % 5 == 0) res = res + i;
}

cout <<endl << res << endl;
return 0;
}
